QJEEAdv19Ch69aa: JEE Advanced 2019 Chemistry - Class 12 JEEAdv19Ch69aa Solution: Consider the following reactions (unbalanced). Z n + H o t c o…

Question

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Consider the following reactions (unbalanced).

Z n + H o t c o n c . H_{2} S O_{4} \underset{}{⟶} G + R + X

Z n + c o n c . N a O H \underset{}{⟶} T + Q

G + H_{2} S + N H_{4} O H \underset{}{⟶} Z (a p r e c i p i t a t e) + X + Y

Choose the correct option(s).

Accepted Answer

When Zn react with hot conc. H₂SO₄ then SO₂ is released and ZnSO₄ is obtained.

R(SO₂) molecule is V-shaped

JEE Advanced 2019 Paper 2 Offline Chemistry - p-Block Elements Question 47 English Explanation 2

Thus, option (b) is correct.

When Zn is react with conc. NaOH then H₂ gas is evolved and Na₂ZnO₂ is obtained.

Z n + 2 N a O H (c o n c .) \underset{}{⟶} \underset{(T)}{N a_{2} Z n O_{2}} + \underset{(Q)}{H_{2}} ↑

In ground state, H

-

H (Q)

(bond order = 1)

Thus, option (c) is correct.

The oxidation state of Zn in T(Na₂ZnO₂) is +2

Thus, option (a) is incorrect.

\underset{(G)}{Z n S O_{4}} + H_{2} S + N H_{4} O H \underset{}{⟶} \underset{(Z)}{Z n S} ↓ + \underset{(X)}{2 H_{2} O} + \underset{(Y)}{{(N H_{4})}_{2} S O_{4}}

ZnS (Z) compound is dirty white coloured.

Thus, option (d) is correct.

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