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QJEEAdv19Ch37a7: JEE Advanced 2019 Chemistry - Class 12 JEEAdv19Ch37a7 Solution: Choose the correct option(s) from the following.

Choose the correct option(s) from the following.

Multiple Choice Options

  • A Teflon is prepared by heating tetrafluoroethene in presence of a persulphate catalyst at high pressure.
  • B Natural rubber is polyisoprene containing trans alkene units
  • C Cellulose has only α\alpha -D-glucose units that are joined by glycosidic linkages
  • D Nylon-6 has amide linkages

Step-by-Step Verified Solution

(a) Teflon is prepared by heating tetrafluoroethene in presence of persulphate catalyst at higher pressure.

JEE Advanced 2019 Paper 2 Offline Chemistry - Polymers Question 6 English Explanation 1
Thus, option (a) is correct.

(b) Natural rubber is a linear polymer of isoprene (2-methyl-1,3-butadiene) also known as cis-1,4-polyisoprene.

JEE Advanced 2019 Paper 2 Offline Chemistry - Polymers Question 6 English Explanation 2
Thus, option (b) is incorrect.

(c) Cellulose has only β\beta -D-glucose units that are joined together by glycosidic linkages as shown in the following structure :

JEE Advanced 2019 Paper 2 Offline Chemistry - Polymers Question 6 English Explanation 3
Thus, option (c) is incorrect.

(d) Nylon-6 has amide linkages.

JEE Advanced 2019 Paper 2 Offline Chemistry - Polymers Question 6 English Explanation 4
Thus, option (d) is correct.

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