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QJEEAdv19Ch356b: JEE Advanced 2019 Chemistry - Class 12 JEEAdv19Ch356b Solution: A tin chloride Q undergoes the following reactions (not…

A tin chloride Q undergoes the following reactions (not balanced)

Q+Cl−→XQ + C{l^ - } \to X

Q+Me3N→YQ + M{e_3}N \to Y

Q+CuCl2→Z+CuClQ + CuC{l_2} \to Z + CuCl

X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds.

Choose the correct option(s).

Multiple Choice Options

  • A There is a coordinate bond in Y
  • B The central atom in Z has one lone pair of electrons.
  • C The oxidation state of the central atom in Z is +2
  • D The central atom in X is sp3 hybridised

Step-by-Step Verified Solution

Sn can exist in +2 or +4 oxidation state. So, Q in the given reactions can be SnCl2 or SnCl4. Since X is monoanion having trigonal pyramidal geometry (sp3 with one lone pair as per VSEPR), so Q is SnCl2, and the first reaction is
JEE Advanced 2019 Paper 1 Offline Chemistry - p-Block Elements Question 48 English Explanation 1
The second reaction is Stephen’s reaction, where nitrile is converted to aldehyde via formation of iminium salt.

JEE Advanced 2019 Paper 1 Offline Chemistry - p-Block Elements Question 48 English Explanation 2 JEE Advanced 2019 Paper 1 Offline Chemistry - p-Block Elements Question 48 English Explanation 3
There is a coordinate bond in the Cl2Sn.N(CH3)3 in between nitrogen and Sn metal.
JEE Advanced 2019 Paper 1 Offline Chemistry - p-Block Elements Question 48 English Explanation 4
Z is oxidised product and oxidation state of Sn is +4 in Z compound. Structure of SnCl4 (Z) is
JEE Advanced 2019 Paper 1 Offline Chemistry - p-Block Elements Question 48 English Explanation 5

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