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QJEEAdv18Mac024: JEE Advanced 2018 Mathematics - Class 11 JEEAdv18Mac024 Solution: Let X be the set consisting of the first 2018 terms of the…

Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ...., and Y be the set consisting of the first 2018 terms of the arithmetic progression 9, 16, 23, .... . Then, the number of elements in the set X ∪ Y is .........

Step-by-Step Verified Solution

Here, X = {1, 6, 11, ....., 10086}

[∵ an = a + (n − 1)d]

and Y = {9, 16, 23, ..., 14128}

X ∩ Y = {16, 51, 86, ...}

tn of X ∩ Y is less than or equal to 10086

∴ tn = 16 + (n − 1) 35 ≤ 10086

⇒ n ≤ 288.7

∴ n = 288

∵ n(X ∩ Y) = n(X) + n(Y) − n(X ∩ Y)

∴ n(X ∩ Y) = 2018 + 2018 − 288 = 3748

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