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QJEEAdv18Mac024: JEE Advanced 2018 Mathematics - Class 11 JEEAdv18Mac024 Solution: Let X be the set consisting of the first 2018 terms of the…
Let X be the set consisting of the first 2018 terms of the arithmetic progression 1, 6, 11, ...., and Y be the set consisting of the first 2018 terms of the arithmetic progression 9, 16, 23, .... . Then, the number of elements in the set X Y is .........
Step-by-Step Verified Solution
Here, X = {1, 6, 11, ....., 10086}
[ an = a + (n 1)d]
and Y = {9, 16, 23, ..., 14128}
X Y = {16, 51, 86, ...}
tn of X Y is less than or equal to 10086
tn = 16 + (n 1) 35 10086
n 288.7
n = 288
n(X Y) = n(X) + n(Y) n(X Y)
n(X Y) = 2018 + 2018 288 = 3748
[
and Y = {9, 16, 23, ..., 14128}
X
tn of X