QJEEAdv18Ch483f: JEE Advanced 2018 Chemistry - Class 11 JEEAdv18Ch483f Solution: A reversible cyclic process for an ideal gas is shown below.…

In the given curve AC represents isochoric process as volume at both the points is same i.e., V₁

Similarly, AB represents isothermal process (as both the points are at T₁ temperature) and BC represents isobaric process as both the points are at p₂ pressure.

Now, (i) for option (a)

q_AC = $$\mathrm{\Delta }$$U_BC = nC_v(T₂ $$-$$ T₁)

where, n = number of moles

C_v = specific heat capacity at constant volume

However, W_AB $$\ne$$ p₂(V₂ $$-$$ V₁) instead

$$W_{AB}=nR{T}_1\ln \left(\frac{V_2}{V_1}\right)$$

So, this option is incorrect.

(ii) For option (b)

where, C_p = specific heat capacity at constant pressure

Likewise,

W_BC = $$-$$p₂(V₁ $$-$$ V₂)

Hence, this option is correct.

(iii) For option (c)

as nC_p(T₂ $$-$$ T₁) < nC_v(T₂ $$-$$ T₁)

so, $$\mathrm{\Delta }$$H_CA < $$\mathrm{\Delta }$$U_CA

and q_AC = $$\mathrm{\Delta }$$U_BC

Hence, this option is also correct.

(iv) For option (d)

Although q_BC = $$\mathrm{\Delta }$$H_AC

but $$\mathrm{\Delta }$$H_CA $$\le$$ $$\mathrm{\Delta }$$U_CA

Hence, this option is incorrect.