Verified Solution • 2025–26 Session
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QJEEAdv18Ch2267: JEE Advanced 2018 Chemistry - Class 12 JEEAdv18Ch2267 Solution: LIST-I contains reactions and LIST-II contains major products.…
LIST-I contains reactions and LIST-II contains major products.
Match the reaction in LIST-I with one or more products in LIST-II and choose the correct option.
Match the reaction in LIST-I with one or more products in LIST-II and choose the correct option.
Multiple Choice Options
- A P−1,5;Q−2;R−3;S−4
- B P−1,4;Q−2;R−4;S−3
- C P−1,4;Q−1,2;R−3,4;S−4
- D P−4,5;Q−4;R−4;S−3,4
Step-by-Step Verified Solution
P. Reactant 1 , acts as a base and abstracts hydrogen from carbon of tert butyl bromide halide (reactant 2 ) forming an alkene and an alcohol.
Elimination proceeds via mechanism. Substitution of reactant 1 is not possible on reactant 2 due to steric crowding at 2.
Q. Reactant 1 (tert butoxide) acts as a base and abstracts proton from acid forming an alcohol and methyl bromide.
R. Sodium methoxide ( is a strong base and abstracts proton from carbon of tert Butyl with simultaneous less of bromide ion forming an alkene.
S. Reactant 1 (tert-butoxide) acts as a nucleophile and attacks from the backside of methyl bromide, with subsequent removal of bromide ion. This is an mechanism.
Elimination proceeds via mechanism. Substitution of reactant 1 is not possible on reactant 2 due to steric crowding at 2.
Q. Reactant 1 (tert butoxide) acts as a base and abstracts proton from acid forming an alcohol and methyl bromide.
R. Sodium methoxide ( is a strong base and abstracts proton from carbon of tert Butyl with simultaneous less of bromide ion forming an alkene.
S. Reactant 1 (tert-butoxide) acts as a nucleophile and attacks from the backside of methyl bromide, with subsequent removal of bromide ion. This is an mechanism.