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QJEEAdv16Ma6098: JEE Advanced 2016 Mathematics - Class 12 JEEAdv16Ma6098 Solution: Football teams and have to play two games against each other.…

Football teams T1{T_1} and T2{T_2} have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of T1{T_1} winning, drawing and losing a game against T2{T_2} are 12,16{1 \over 2},{1 \over 6} and 13{1 \over 3} respectively. Each team gets 33 points for a win, 11 point for a draw and 00 point for a loss in a game. Let XX and YY denote the total points scored by teams T1{T_1} and T2{T_2} respectively after two games.

\,\,\,\,P\,\left( {X > Y} \right) is

Multiple Choice Options

  • A 14{1 \over 4}
  • B 512{5 \over 12}
  • C 12{1 \over 2}
  • D 712{7 \over 12}

Step-by-Step Verified Solution

∙\bullet Probability of wining of T1 against T2 is = 1/2.

∙\bullet Probability of drawing of T1 against T2 is = 1/6.

∙\bullet Probability of losing of T1 against T2 is = 1/3.

∙\bullet 3 points for win.

∙\bullet 1 point for draw.

∙\bullet 0 point for loss.

Here, P(X > Y) = P(T1 win) P(T1 win) + P(T1 win) P(draw) + P(draw) P(T1 win)

=(12×12)+(12×16)+(16×12)=512= \left( {{1 \over 2} \times {1 \over 2}} \right) + \left( {{1 \over 2} \times {1 \over 6}} \right) + \left( {{1 \over 6} \times {1 \over 2}} \right) = {5 \over {12}}

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