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QJEEAdv15Chc99e: JEE Advanced 2015 Chemistry - Class 12 JEEAdv15Chc99e Solution: Three moles of B 2 H 6 are completely reacted with methanol.…
Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing product formed is ____________.
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The reaction is
B2H6 + 6CH3OH 2B(OCH3)3 + 6H2
From the reaction, 1 mol of B2H6 reacts with 6 mol of CH3OH to produce 2 mol of B(OCH3)3.
Therefore, 3 mol of B2H6 would react with 18 mol of CH3OH to produce 6 mol of B(OCH3)3.