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QJEEAdv14Maeafe: JEE Advanced 2014 Mathematics - Class 11 JEEAdv14Maeafe Solution: Let be nonzero real numbers. Let and be distinct points on the…

Let a,r,s,ta, r, s, t be nonzero real numbers. Let P  (at2,2at),  Q,   R  (ar2,2ar)P\,\,\left( {a{t^2},2at} \right),\,\,Q,\,\,\,R\,\,\left( {a{r^2},2ar} \right) and S  (as2,2as)S\,\,\left( {a{s^2},2as} \right) be distinct points on the parabola y2=4ax{y^2} = 4ax . Suppose that PQPQ is the focal chord and lines QRQR and PKPK are parallel, where KK is the point (2a,0)(2a,0)

The value of rr is

Multiple Choice Options

  • A −1t- {1 \over t}
  • B t2+1t{{{t^2} + 1} \over t}
  • C 1t{1 \over t}
  • D t2−1t{{{t^2} - 1} \over t}

Step-by-Step Verified Solution

Given, four points P(at2,2at),Q,R(ar2,2ar)\mathrm{P}\left(a t^2, 2 a t\right), \mathrm{Q}, \mathrm{R}\left(a r^2, 2 a r\right) and S(as2,2as)S\left(a s^2, 2 a s\right) be distinct points on the parabola y2=4axy^2=4 a x .

Also given PQ is the focal chord of parabola

amp;y2=4axamp;∴Q=(at2,−2at)\begin{aligned}& y^2=4 a x \\& \therefore \quad \mathrm{Q}=\left(\frac{a}{t^2},-\frac{2 a}{t}\right)\end{aligned}

JEE Advanced 2014 Paper 2 Offline Mathematics - Parabola Question 20 English Explanation

Given, K=(2a,0)\mathrm{K}=(2 a, 0) and PK is parallel to QR

∴\therefore Slope of line PK == Slope of line QR

amp;2at−0at2−2a=2ar+2atar2−at2⇒amp;tt2−2=r+1tr2−1t2⇒amp;tt2−2=r+1t(r+1t)(r−1t)⇒amp;tt2−2=1r−1t⇒amp;tr−1=t2−2⇒amp;r=t2−1t\begin{aligned}& \frac{2 a t-0}{a t^2-2 a}=\frac{2 a r+\frac{2 a}{t}}{a r^2-\frac{a}{t^2}} \\\Rightarrow & \frac{t}{t^2-2}=\frac{r+\frac{1}{t}}{r^2-\frac{1}{t^2}} \\\Rightarrow & \frac{t}{t^2-2}=\frac{r+\frac{1}{t}}{\left(r+\frac{1}{t}\right)\left(r-\frac{1}{t}\right)} \\\Rightarrow & \frac{t}{t^2-2}=\frac{1}{r-\frac{1}{t}} \\\Rightarrow & t r-1=t^2-2 \\\Rightarrow & \quad r=\frac{t^2-1}{t}\end{aligned}

Hint:

(i) If PQ is a focal chord of parabola y2=4axy^2=4 a x and P=(at2,2at)\mathrm{P}=\left(a t^2, 2 a t\right) , then Q=(at2,−2at)\mathrm{Q}=\left(\frac{a}{t^2},-\frac{2 a}{t}\right) .

(ii) If two lines are parallel, then their slopes are equal.

(iii) The slope of line passing through two points (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right) is y2−y1x2−x1\frac{y_2-y_1}{x_2-x_1} .

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