Let A, B, C, D are the events of solving a problem.
Given: P(A)=21,P(B)=43,P(C)=41,P(D)=81
Also given A, B, C, D are independent events.
Let P is the probability of solved by at least one person.
⇒P=1− (Probability that none of the person can solve the problem)
amp;⇒P=1−P(A∩B∩C∩D)amp;⇒P=1−P(A)⋅P(B)⋅P(C)⋅P(D)amp;⇒P=1−(1−P(A))(1−P(B))(1−P(C))(1−P(D))amp;⇒P=1−(1−21)(1−43)(1−41)(1−81)amp;⇒P=1−21×41×43×87amp;⇒P=1−25621amp;⇒P=256235
Hints:
⇒ (i) If A and B are independent events, then
amp;→P(A∩B)=P(A)⋅P(B)amp;→P(A∩B)=P(A)⋅P(B)=(1−P(A))(1−P(B))amp;→P(A∩B)=P(A)⋅P(B)=(1−P(A))P(B)amp;→P(A∩B)=P(A)⋅P(B)=P(A)⋅(1−P(B))
(ii) Probability of at least one person can solve the problem =1− Probability that none of the persons can solve that problem.