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QJEEAdv07Phb749: JEE Advanced 2007 Physics - Class 12 JEEAdv07Phb749 Solution: Positive and negative point charges of equal magnitude are kept …

Positive and negative point charges of equal magnitude are kept at (0,0,a2)\left(0,0, \frac{a}{2}\right) and (0,0,−a2)\left(0,0, \frac{-a}{2}\right) , respectively. The work done by the electric field when another positive point charge is moved from (−a,0,0)(-a, 0,0) to (0,a,0)(0, a, 0) is

Multiple Choice Options

  • A positive
  • B negative
  • C zero
  • D depends on the path connecting the initial and final positions

Step-by-Step Verified Solution

Consider that,

P=(−a,0,0)\mathrm{P}=(-a, 0,0) and Q=(0,a,0)\mathrm{Q}=(0, a, 0) points lie on the equatorial plane of dipole.

The charges makes an electric dipole.

Therefore, potential at P=\mathrm{P}= Potential at Q=0\mathrm{Q}=0

Work done (W)=q( VP−VQ)=0(\mathrm{W})=q\left(\mathrm{~V}_{\mathrm{P}}-\mathrm{V}_{\mathrm{Q}}\right)=0

IIT-JEE 2007 Paper 2 Offline Physics - Electrostatics Question 6 English Explanation

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