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QJEEAdv07Ph5b89: JEE Advanced 2007 Physics - Class 12 JEEAdv07Ph5b89 Solution: A magnetic field B → = B 0 j ^ exists in the region a < x < 2 a …

A magnetic field B→=B0j^ exists in the region a<x<2a and B→=−B0j^, in the region 2a<x<3a, where B0 is a positive constant. A positive point charge moving with a velocity v→=v0i^, where v0 is a positive constant, enters the magnetic field at x=a. The trajectory of the charge in this region can be like,

IIT-JEE 2007 Paper 2 Offline Physics - Magnetism Question 6 English

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/35fbdb79df95155509908837b8f68837c492f7cb0b9d2dd0c7633bbe1c57bf22.webp
  • B https://ik.imagekit.io/novatra/photos/727aceb3b6bc536b03fcf7f54c2712ee9e2de04d24c92069a6b1c30334e235f9.webp
  • C https://ik.imagekit.io/novatra/photos/565d1737d89a8efdec5c935a5d263a11fd1f7e6b12de80208ff6c4370699e680.webp
  • D https://ik.imagekit.io/novatra/photos/77417c4a7b0b24003f94c67d2de7b09ac4cef18ced5f6370b09d8631e2f98915.webp

Step-by-Step Verified Solution

For a<x<2a

B→=B0j^

The initial velocity is v→=v⋅j^

IIT-JEE 2007 Paper 2 Offline Physics - Magnetism Question 6 English Explanation

From the above diagram it is clear that force on the particle is toward +z-axis (by applying Fleming's left hand rule) at x=a, which shifts the particle as shown in the x-z plane

For 2a<x<3a

B→=−B0j^

The direction of velocity is shown at x=2a.

Again by using Fleming's left hand rule, we get direction of force.

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