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QJEEAdv07Che342: JEE Advanced 2007 Chemistry - Class 12 JEEAdv07Che342 Solution: Consider a reaction aG + bH Products. When concentration of…

Consider a reaction aG + bH →\to Products. When concentration of both the reactants G and H is doubled, the rate increases by eight times. However, when concentration of G is doubled keeping the concentration of H fixed, the rate is doubled. The overall order of the reaction is

Multiple Choice Options

  • A 0
  • B 1
  • C 2
  • D 3

Step-by-Step Verified Solution

The rate law expression is

R=k[G]a[H]b\mathrm{R}=k[\mathrm{G}]^{a}[\mathrm{H}]^{b} ...... (i)

The rate of reaction increases by a factor of 2 on doubling the concentration of ' G\mathrm{G} '.

The rate law expression becomes

R′=2R=k2a[G]a[H]b\mathrm{R}^{\prime}=2 \mathrm{R}=k 2^{a}[\mathrm{G}]^{a}[\mathrm{H}]^{b} ..... (ii)

Divided equation (ii) with eqn. (i)

R′Ramp;=2RR=k2a[G]a[H]bk2[G]a[H]b2amp;=2aaamp;=1\begin{aligned}\frac{\mathrm{R}^{\prime}}{\mathrm{R}} & =\frac{2 \mathrm{R}}{\mathrm{R}}=\frac{k 2^{a}[\mathrm{G}]^{a}[\mathrm{H}]^{b}}{k 2[\mathrm{G}]^{a}[\mathrm{H}]^{b}} \\2 & =2^{a} \\a & =1\end{aligned}

The rate of reaction increases by a factor of 8 on doubling the concentration of G\mathrm{G} and ' H\mathrm{H} '.

The rate law expression becomes

Rate =R′′k2a[G]a2b[H]b=\mathrm{R}^{\prime \prime} k 2^{a}[\mathrm{G}]^{a} 2^{b}[\mathrm{H}]^{b} ..... (iii)

Divide equation (iii) with equation (i)

8RRamp;=k2a[G]a2b[H]bk[G]a[H]b\begin{aligned}\frac{8 \mathrm{R}}{\mathrm{R}} & =\frac{k 2^{a}[\mathrm{G}]^{a} 2^{b}[\mathrm{H}]^{b}}{k[\mathrm{G}]^{a}[\mathrm{H}]^{b}}\end{aligned}

8=2a2b8=2^a2^b

or b=2b=2

The overall order of reaction is

a+b=1+2=3a+b=1+2=3

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