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QJEEAdv06Ma870f: JEE Advanced 2006 Mathematics - Class 11 JEEAdv06Ma870f Solution: The axis of a parabola is along the line and the distances of…

The axis of a parabola is along the line y=xy = x and the distances of its vertex and focus from origin are 2\sqrt 2 and 222\sqrt 2 respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is

Multiple Choice Options

  • A (x+y)2=(x−y−2){\left( {x + y} \right)^2} = \left( {x - y - 2} \right)
  • B (x−y)2=(x+y−2){\left( {x - y} \right)^2} = \left( {x + y - 2} \right)
  • C (x−y)2=4(x+y−2){\left( {x - y} \right)^2} = 4\left( {x + y - 2} \right)
  • D (x−y)2=8(x+y−2){\left( {x - y} \right)^2} = 8\left( {x + y - 2} \right)

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