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QJEEAdv06Ma6e3e: JEE Advanced 2006 Mathematics - Class 12 JEEAdv06Ma6e3e Solution: A curve passes through and at tangent cuts the -axis and -axis…

A curve y=f(x)y=f(x) passes through (1,1)(1,1) and at P(x,y),P(x,y), tangent cuts the xx -axis and yy -axis at AA and BB respectively such that BP:AP=3:1,BP:AP=3:1, then

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  • A equation of curve is xy′−3y=0xy'-3y=0
  • B normal at (1,1)(1,1) is x+3y=4x+3y=4
  • C curve passes through (2,1/8)(2, 1/8)
  • D equation of curve is xy′+3y=0xy'+3y=0

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