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QJEEAdv06Ma6bbe: JEE Advanced 2006 Physics - Class 11 JEEAdv06Ma6bbe Solution: Match the folowing : (A) Two rays and intersects each other in…

Match the folowing :
(A)    \,\,\, Two rays x+y=∣a∣x + y = \left| a \right| and ax−y=1ax - y=1 intersects each other in the
          \,\,\,\,\,\,\,\,\,\, first quadrant in interval a∈(a0,  ∞),a \in \left( {{a_0},\,\,\infty } \right), the value of a0{{a_0}} is
(B)    \,\,\, Point (α,β,γ)\left( {\alpha ,\beta ,\gamma } \right) lies on the plane x+y+z=2.x+y+z=2.
           \,\,\,\,\,\,\,\,\,\,\, Let a→=αi^+βj^+γk^,k^×(k^×a→)=0,\overrightarrow a = \alpha \widehat i + \beta \widehat j + \gamma \widehat k,\widehat k \times \left( {\widehat k \times \overrightarrow a } \right) = 0, then γ=\gamma =
(C)    \,\,\, ∣∫01(1−y2)dy∣+∣∫10(y2−1)dy∣\left| {\int\limits_0^1 {\left( {1 - {y^2}} \right)dy} } \right| + \left| {\int\limits_1^0 {\left( {{y^2} - 1} \right)dy} } \right|
(D)    \,\,\, If sin⁡A  sin⁡B  sin⁡C+cos⁡A  cos⁡B=1,\sin A\,\,\sin B\,\,\sin C + \cos A\,\,\cos B = 1, then the value of sin⁡C=\sin C =

(p)    \,\,\, 22
(q)    \,\,\, 43{4 \over 3}
(r)    \,\,\, ∣∫011−xdx∣+∣∫−101+xdx∣\left| {\int\limits_0^1 {\sqrt {1 - xdx} } } \right| + \left| {\int\limits_{ - 1}^0 {\sqrt {1 + xdx} } } \right|
(s)    \,\,\, 11

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