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QJEEAdv06Ma5ba0: JEE Advanced 2006 Mathematics - Class 11 JEEAdv06Ma5ba0 Solution: In Δ A B C , internal angle bisector of ∠ A meets side B C in D …

In ΔABC, internal angle bisector of ∠A meets side BC in D. DE⊥AD meets AC in E and AB in F. Then

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  • A AE is HM of b and c
  • B AD =2bcb+ccos⁡A2
  • C EF =4bcb+csin⁡A2
  • D ΔAEF is isosceles

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