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QJEEAdv06Ma3556: JEE Advanced 2006 Mathematics - Class 12 JEEAdv06Ma3556 Solution: Match the following Column (A) then tan (B) Sides of a triangle …

Match the following

Column II

(A) ∑i=1∞tan⁡−1(12i2)=t,\sum\limits_{i = 1}^\infty {{{\tan }^{ - 1}}\left( {{1 \over {2{i^2}}}} \right) = t,} then tan t=t=

(B) Sides a,b,ca, b, c of a triangle ABCABC are in APAP and
cos⁡θ1=ab+c, cos⁡θ2=ba+c,cos⁡θ3=ca+b,\cos {\theta _1} = {a \over {b + c}},\,\cos {\theta _2} = {b \over {a + c}},\cos {\theta _3} = {c \over {a + b}},
then tan⁡2(θ12)+tan⁡2(θ32)={\tan ^2}\left( {{{{\theta _1}} \over 2}} \right) + {\tan ^2}\left( {{{{\theta _3}} \over 2}} \right) =

(C) A line is perpendicular to x+2y+2z=0x + 2y + 2z = 0 and
passes through (0,1,0)(0, 1, 0) . The perpendicular distance of this line from the origin is

Column IIII

(p) 11

(q) 53{{\sqrt 5 } \over 3}

(r) 23{2 \over 3}

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