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QJEEAdv05Phde37: JEE Advanced 2005 Physics - Class 11 JEEAdv05Phde37 Solution: A simple pendulum has time period T 1 . The point of suspension …

A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y = Kt2, (K = 1 m/s2) where y is the vertical displacement. The time period now become T2. The ratio of T12T22{{T_1^2} \over {T_2^2}} is (g = 10 m/s2)

Multiple Choice Options

  • A 56{5 \over 6}
  • B 65{6 \over 5}
  • C 1
  • D 45{4 \over 5}

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