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QJEEAdv05Maf9bf: JEE Advanced 2005 Mathematics - Class 12 JEEAdv05Maf9bf Solution: The solution of primitive integral equation is If and , then is …

The solution of primitive integral equation (x2+y2)dy=xy\left( {{x^2} + {y^2}} \right)dy = xy
dxdx is y=y(x),y=y(x), If y(1)=1y(1)=1 and (x0)=e\left( {{x_0}} \right) = e , then x0{{x_0}} is equal to

Multiple Choice Options

  • A 2(e2−1)\sqrt {2\left( {{e^2} - 1} \right)}
  • B 2(e2+1)\sqrt {2\left( {{e^2} + 1} \right)}
  • C 3 e\sqrt 3 \,e
  • D 2(e2+1)2\sqrt {{{2\left( {{e^2} + 1} \right)} \over 2}}

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