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QJEEAdv05Mabde3: JEE Advanced 2005 Mathematics - Class 11 JEEAdv05Mabde3 Solution: Find the equation of the common tangent in quadrant to the…

Find the equation of the common tangent in 1st{1^{st}} quadrant to the circle x2+y2=16{x^2} + {y^2} = 16 and the ellipse x225+y24=1{{{x^2}} \over {25}} + {{{y^2}} \over 4} = 1 . Also find the length of the intercept of the tangent between the coordinate axes.

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