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QJEEAdv05Ma28ad: JEE Advanced 2005 Physics - Class 11 JEEAdv05Ma28ad Solution: If are three non-zero, non-coplanar vectors and then the set of …

If a→ , b→,c→\overrightarrow a \,,\,\overrightarrow b ,\overrightarrow c are three non-zero, non-coplanar vectors and
b1→=b→−b→. a→∣a→∣2a→,b2→=b→+b→. a→∣a→∣2a→,\overrightarrow {{b_1}} = \overrightarrow b - {{\overrightarrow b .\,\overrightarrow a } \over {{{\left| {\overrightarrow a } \right|}^2}}}\overrightarrow a ,\overrightarrow {{b_2}} = \overrightarrow b + {{\overrightarrow b .\,\overrightarrow a } \over {{{\left| {\overrightarrow a } \right|}^2}}}\overrightarrow a ,
c1→=c→−c→. a→∣a→∣2a→+b→. c→∣c∣2b→1,  c2→=c→−c→. a→∣a→∣2a→−b→ . c→∣b→1∣2b→1,\overrightarrow {{c_1}} = \overrightarrow c - {{\overrightarrow c .\,\overrightarrow a } \over {{{\left| {\overrightarrow a } \right|}^2}}}\overrightarrow a + {{\overrightarrow b .\,\overrightarrow c } \over {{{\left| c \right|}^2}}}{\overrightarrow b _1},\,\,\overrightarrow {{c_2}} = \overrightarrow c - {{\overrightarrow c .\,\overrightarrow a } \over {{{\left| {\overrightarrow a } \right|}^2}}}\overrightarrow a - {{\overrightarrow b \,.\,\overrightarrow c } \over {{{\left| {{{\overrightarrow b }_1}} \right|}^2}}}{\overrightarrow b _1},
c3→=c→−c→. a→∣c→∣2a→+b→. c→∣c∣2b→1,  c4→=c→−c→. a→∣c→∣2a→−b→ . c→∣b→1∣2b→1,\overrightarrow {{c_3}} = \overrightarrow c - {{\overrightarrow c .\,\overrightarrow a } \over {{{\left| {\overrightarrow c } \right|}^2}}}\overrightarrow a + {{\overrightarrow b .\,\overrightarrow c } \over {{{\left| c \right|}^2}}}{\overrightarrow b _1},\,\,\overrightarrow {{c_4}} = \overrightarrow c - {{\overrightarrow c .\,\overrightarrow a } \over {{{\left| {\overrightarrow c } \right|}^2}}}\overrightarrow a - {{\overrightarrow b \,.\,\overrightarrow c } \over {{{\left| {{{\overrightarrow b }_1}} \right|}^2}}}{\overrightarrow b _1},
then the set of orthogonal vectors is

Multiple Choice Options

  • A (a→,b1→,c3→)\left( {\overrightarrow a ,\overrightarrow {{b_1}} ,\overrightarrow {{c_3}} } \right)
  • B (a→,b1→,c2→)\left( {\overrightarrow a ,\overrightarrow {{b_1}} ,\overrightarrow {{c_2}} } \right)
  • C (a→,b1→,c1→)\left( {\overrightarrow a ,\overrightarrow {{b_1}} ,\overrightarrow {{c_1}} } \right)
  • D (a→,b2→,c2→)\left( {\overrightarrow a ,\overrightarrow {{b_2}} ,\overrightarrow {{c_2}} } \right)

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