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QJEEAdv03Maa180: JEE Advanced 2003 Mathematics - Class 11 JEEAdv03Maa180 Solution: If and (where ), then is

If  ∣z∣=1\,\left| z \right| = 1 and ω=z−1z+1\omega = {{z - 1} \over {z + 1}} (where z≠−1z \ne - 1 ), then Re(ω){\mathop{\rm Re}\nolimits} \left( \omega \right) is

Multiple Choice Options

  • A 0
  • B −1∣z+1∣2- {1 \over {{{\left| {z + 1} \right|}^2}}}
  • C ∣zz+1∣.1∣z+1∣2\left| {{z \over {z + 1}}} \right|.{1 \over {{{\left| {z + 1} \right|}^2}}}
  • D  2∣z+1∣2\,{{\sqrt 2 } \over {{{\left| {z + 1} \right|}^2}}}

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