QJEEAdv03Cha41e: JEE Advanced 2003 Chemistry - Class 12 JEEAdv03Cha41e Solution: 1 gm of charcoal adsorbs 100 ml 0.5 M CH 3 COOH to form a…

The number of moles of acetic acid in 100 mL (before adding charcoal) = 0.05 mol

The number of moles of acetic acid in 100 mL (after adding charcoal) = 0.049 mol

The number of moles of acetic acid adsorbed on the surface of charcoal = 0.05 - 0.049 = 0.001 mol

The number of molecules of acetic acid adsorbed on the surface of charcoal = 0.001 $$\times$$ 6.02 $$\times$$ 10²³ = 6.02 $$\times$$ 10²⁰

Given that the surface area of charcoal = 3.01 $$\times$$ 10² m² , so the area occupied by single acetic acid molecule on the surface of charcoal is

= $$\frac{3.01\times {10}^2}{6.02\times {10}^{20}}$$ = 5 $$\times$$ 10^-19 m²