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QJEEAdv02Maca6e: JEE Advanced 2002 Mathematics - Class 12 JEEAdv02Maca6e Solution: Let Then the real roots of the equation are

Let f(x)=∫1x2−t2 dt.f\left( x \right) = \int\limits_1^x {\sqrt {2 - {t^2}} \,dt.} Then the real roots of the equation
x2−f′(x)=0{x^2} - f'\left( x \right) = 0 are

Multiple Choice Options

  • A ±1\pm 1
  • B ±12\pm {1 \over {\sqrt 2 }}
  • C ±12\pm {1 \over 2}
  • D 00 and 11

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