QJEEAdv02Ma782d: JEE Advanced 2002 Mathematics - Class 11 JEEAdv02Ma782d Solution: If a > 2 b > 0 then the positive value of m for which y = m x − …

Question

Verified Solution • 2025–26 Session moderate

If

a > 2 b > 0

then the positive value of

m

for which

y = m x - b \sqrt{1 + m^{2}}

is a common tangent to

x^{2} + y^{2} = b^{2}

and

{(x - a)}^{2} + y^{2} = b^{2}

is

Accepted Answer

Answer

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