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QJEEAdv02Ma1606: JEE Advanced 2002 Mathematics - Class 11 JEEAdv02Ma1606 Solution: The equation of the common tangent to the curves and is

The equation of the common tangent to the curves y2=8x{y^2} = 8x and xy=−1xy = - 1 is

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  • A 3y=9x+23y = 9x + 2
  • B y=2x+1y = 2x + 1
  • C 2y=x+82y = x + 8
  • D y=x+2y= x + 2

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