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QJEEAdv02Ma04e4: JEE Advanced 2002 Mathematics - Class 12 JEEAdv02Ma04e4 Solution: The point(s) in the curve where the tangent is vertical, is (are)

The point(s) in the curve y3+3x2=12y{y^3} + 3{x^2} = 12y where the tangent is vertical, is (are)

Multiple Choice Options

  • A (±43,−2)\left( { \pm {4 \over {\sqrt 3 }}, - 2} \right)
  • B (±113,1)\left( { \pm \sqrt {{{11} \over 3}} ,1} \right)
  • C (0,0)(0,0)
  • D (±43,2)\left( { \pm {4 \over {\sqrt 3 }}, 2} \right)

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